If the probabilities of four mutually exclusive and exhaustive events P, Q, R and S satisfy the relation
3P(P) = P(Q) = 2P(R) = 4P(S), then P(Q) is:
1
\(\frac{8}{25}\)
2
\(\frac{19}{25}\)
3
\(\frac{17}{25}\)
4
\(\frac{12}{25}\)
If the probabilities of four mutually exclusive and exhaustive events P, Q, R and S satisfy the relation
3P(P) = P(Q) = 2P(R) = 4P(S), then P(Q) is: