If Δ ABC~Δ FDE such that AB = 9 cm, AC = 11 cm, DF = 16 cm and DE = 12 cm, then the length of BC is:

1
\(5\frac{3}{4}\) cm
2
\(4\frac{3}{5}\) cm
3
\(3\frac{5}{7}\) cm
4
\(6\frac{3}{4}\) cm

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