Given that ΔDEF ~ ΔABC. If the area of ΔABC is 9 cm2 and area of ΔDEF is 12cm2 , BC = 2.1 cm, then the length of EF is:

1
\(\frac{8\sqrt3}{5}cm\)
2
\(\frac{3\sqrt7}{5}cm\)
3
\(\frac{4\sqrt7}{5}cm\)
4
\(\frac{7\sqrt3}{5}cm\)

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