(i) x ≠  –16 మరియు (ii) x2+ 32x = 320 అయితే \(\frac{16}{(x+16)^2}\) విలువ ఏమిటి?

1
36
2
\(\frac{1}{576}\)
3
\(\frac{1}{320}\)
4
\(\frac{1}{36}\)

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