\(1\div \frac{3}{7}\rm \ of \ (6+8\times \overline {3-2}) \left[\frac{1}{5}\div \frac{7}{25}-\left\{\frac{3}{7}+\frac{8}{14}\right\}\right] = \)

1
\(\frac{-7}{12}\)
2
\(\frac{-4}{45}\)
3
\(\frac{3}{70}\)
4
\(\frac{5}{49}\)

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