1 2 + 2 2 + 3 2 + ... + x 2 = \(\frac{x(x+1)(2x+1)}{6}\) , అప్పుడు 1 2 + 3 2 + 5 2 + ... + 19 2 =

1
1330
2
2100
3
2485
4
2500

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