y + \(\frac{1}{y}\) = 8 అయితే, \(\frac{4y}{3y^2 + 3 - 2y}\) విలువను కనుగొనండి.

1
\(\frac{2}{11}\)
2
\(\frac{3}{11}\)
3
\(\frac{4}{11}\)
4
\(\frac{5}{11}\)

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