a2 + b2 + 64c2 + 16c + 3 = 2(a + b), అయితే  3a7 + b7 + 6c2 విలువ?

1
\(6{3\over 32}\)
2
\(4{7\over8}\)
3
\(3{7\over 8}\)
4
\(4{3\over32}\)

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