\(2x + 3y\; = \;\frac{{11}}{2}\) మరియు \(xy\; = \;\frac{5}{6}\), అయితే అప్పుడు 8x3 + 27y3 విలువ

1
583
2
\(\frac{{583}}{4}\)
3
187
4
\(\frac{{671}}{8}\)

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