tan(A + B) = 0 అయితే, అప్పుడు-

1
tan A + tan B = 0
2
tan A = tan B
3
\(\frac{{2\tan A\; + \;\tan B}}{{1\; - \;\tan A\tan B}} = 1\)
4
\(\frac{{2\tan A\; + \;\tan B}}{{1\; + \;\tan A\tan B}} = 0\)

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