Tn = \(\frac{2(n+2)}{n(n+1)}\), n = 1, 2, 3, ... అయితే అప్పుడు T6 =

1
\(\frac{8}{18}\)
2
\(\frac{8}{19}\)
3
\(\frac{8}{20}\)
4
\(\frac{8}{21}\)

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