టాన్ θ = \(\rm \frac{\sqrt{q^2-p^2}}{p}\) ; 0 < θ < 90°, అప్పుడు sec θ + cos θ + 2 అంటే ఏమిటి ?

1
\(\rm \frac{p^2+q^2}{pq}\)
2
\(\rm \frac{(p+q)^2}{pq}\)
3
\(\rm \frac{(p+q)^2}{2pq}\)
4
\(\rm \frac{(pq)^2}{pq}\)

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