ఇచ్చిన అణు ప్రతిచర్యలో, మూలకం X:

\({ }_{11}^{22} \mathrm{Na}\) → X + e + + v

1
\({ }_{12}^{22} \mathrm{Mg}\)
2
\({ }_{11}^{23} \mathrm{Na}\)
3
\({ }_{10}^{23} \mathrm{Na}\)
4
\({ }_{10}^{22} \mathrm{Ne}\)

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