Quantitative Aptitude Geometry Triangles, Congruence and Similarity

Δ ABC ~ Δ PQR \(\rm \frac{ar(ABC) } {ar(PQR) }=\rm \frac{ 9} { 4 }\) అయితే, AB = 18 సెం.మీ మరియు BC = 15 సెం.మీ, అప్పుడు QR=?

1
10 సెం.మీ
2
12 సెం.మీ
3
\(\rm \frac{20 } {3 }\) సెం.మీ
4
8 సెం.మీ

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