కింది వ్యక్తీకరణ యొక్క ఫలితం ఏమిటి?

\(\frac{{{{\sec }^2}x + {{\tan }^2}x}}{{{{\sin }^2}x + 1}} = ?\)

1
0
2
\(\frac{1}{{{{\sin }^2}x}}\)
3
-cos2x
4
\(\frac{1}{{{{\cos }^2}x}}\)

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