cos θ = \(\frac{4x}{1 + 4x^2}\) అయితే sin θ యొక్క విలువ ఏమిటి?

1
\(\frac{1 - 4x^2}{4x}\)
2
\(\frac{1 - 4x^2}{1+4x^2}\)
3
\(\frac{1 + 4x^2}{1-4x^2}\)
4
\(\frac{1 + 4x^2}{4x^2}\)

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