2x = 4y = 8z மற்றும் \(\frac{1}{2x}+\frac{1}{4y}+\frac{1}{4z}=4\), எனில், xஇன் மதிப்பு என்ன?

1
\(\frac{7}{16}\)
2
\(\frac{7}{17}\)
3
\(\frac{7}{19}\)
4
\(\frac{7}{23}\)

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