ତ୍ରିଭୁଜ ABC ରେ, ଯଦି AD ହେଉଛି ∠BAC କୋଣର ସମଦ୍ଵିଖଣ୍ଡକ, AE ⊥ BC, ̈́∠B = 30° ଏବଂ ̈́∠C = 50°, ତେବେ ∠DAE ହେଉଛି:
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