ଯଦି \(\left(\dfrac{5}{7}\right)^4 \times \left(\dfrac{5}{7}\right)^{-3} = \left(\dfrac{5}{7}\right)^{5x-2}\)  ହୁଏ, ତେବେ x ହେଉଛି 

1
\(\dfrac{1}{5}\)
2
\(\dfrac{2}{5}\)
3
\(\dfrac{3}{5}\)
4
\(\dfrac{4}{5}\)

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