ଯଦି\(7 b-\frac{1}{4 b}=7\), ତେବେ \(16 b^2+\frac{1}{49 b^2}\) ର ମୂଲ୍ୟ କେତେ ?

1
\( \frac{80}{49} \)
2
\( \frac{104}{7} \)
3
\(\frac{120}{7} \)
4
\( \frac{7}{2}\)

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