ଏହା ଦିଆଯାଇଛି ଯେ  Δ ABC ~ Δ PQR,  \(\rm \frac{BC } { QR }=\rm \frac{1 } {3 }\)| ତା'ହେଲେ \(\rm \frac{ar(PRQ) } {ar(BCA) }\) ହେଉଛି 

1
9
2
3
3
\(\rm \frac{1 } { 3 }\)
4
\( \frac{1 } { 9 }\)

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