जर Sinθ – \(\sqrt{3}\) cosθ = 0 (θ हा एक लघुकोन आहे), तर sin2θ – cos2θ = ?

1
\(\frac{1}{2}\)
2
1
3
\(\frac{\sqrt3 - 1}{2}\)
4
\(\frac{1}{2}\)

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