द्विघात समीकरणाचे \(x = \frac 1 {11}\) आणि \(x = \frac {-1} {9}\) असे दोन मूळ आहेत. खालील प्रकारे समीकरण कसे लिहिता येईल?

1
(11x - 1)(9x - 1) = 0
2
(11x - 1)(9x + 1) = 0
3
(11x + 1)(9x - 1) = 0
4
(11x + 1)(9x + 1) = 0

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