जर \(tan40^0 = \alpha\) , तर \(\frac{tan320^0 - tan 310^0}{1 + tan320^0.tan 310^0}\) शोधा.

1
\(\frac{1 - \alpha^2}{\alpha}\)
2
\(\frac{1 + \alpha^2}{2\alpha}\)
3
\(\frac{1 - \alpha^2}{2\alpha}\)
4
\(\frac{1 +\alpha^2}{\alpha}\)

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