जर α आणि β ही x2 + 2x + 4 = 0 या समीकरणाची मूळे असतील तर \(\frac{1}{\alpha^3}+\frac{1}{\beta^3}\)  = ?

1
\(-\frac{1}{2}\)
2
\(\frac{1}{2}\)
3
32
4
\(\frac{1}{4}\)

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