\(x + \frac{1}{x}\; = \;6,x \ne 0,\) ആണെങ്കിൽ \(\frac{{{x^2} + \;3x\; + \;1}}{{{x^4}\; + \;{x^{ - 2}}}}\) എത്രയായിരിക്കും:

1
\(\frac{1}{{12}}\)
2
\(\frac{1}{{14}}\)
3
\(\frac{1}{{24}}\)
4
\(\frac{1}{{22}}\)

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