\(\frac{9}{15} \times \frac{45}{81} \times\left\{\frac{49}{6} \times\left(\frac{16}{7}−2\right)\right\} \times \frac{24}{5} \div \frac{16}{15}\) = ?

1
\(\frac{5}{9}\)
2
\(\frac{7}{2}\)
3
\(\frac{2}{7}\)
4
\(\frac{9}{5}\)

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