\(\sqrt {3} \sin \theta - \cos \theta = 0 \)  (\(\theta\) ഒരു ന്യൂനകോൺ ആണ്), അപ്പോൾ ഇതിന്റെ മൂല്യം \(\cos^3\theta - \sqrt 3 \sin^3 \theta\) ഇതായിരിക്കും:

1
–1
2
\(\frac{\sqrt 3}{4}\)
3
\(\frac{\sqrt 3}{2}\)
4
\(\frac{3}{8}\)

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