0∘ < θ < 90എന്നതിന്,  tanθ = \(\frac{a^2 - b^2}{2ab}\)ആണെങ്കിൽ, ​sinθ യുടെ മൂല്യം കണ്ടെത്തുക.

1
\(\frac{a^2 + b^2}{a^2 - b^2}\)
2
\(\frac{2ab}{a^2 + b^2}\)
3
\(\frac{a^2 b^2}{a^2 + b^2}\)
4
\(\frac{a^2 - b^2}{a^2 + b^2}\)

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