3(sec 2 θ + tan 2 θ) = 5, 0° < θ < 90° ಆಗಿದ್ದರೆ, cosec θ ನ ಮೌಲ್ಯವು ಹೀಗಿರುತ್ತದೆ:

1
\(\dfrac{1}{2}\)
2
\(\dfrac{1}{\sqrt3}\)
3
2
4
\(\dfrac{2\sqrt3}{3}\)

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