ΔPQR ಲಂಬಕೋನ ತ್ರಿಕೋನವಾಗಿದೆ. ∠Q = 90 ಡಿಗ್ರಿ, PQ = 9 ಸೆಂ.ಮೀ ಮತ್ತು QR = 11 ಸೆಂ.ಮೀ. cot P ನ ಮೌಲ್ಯ ಎಷ್ಟು?

1
\(\frac{\sqrt{202}}{9}\)
2
\(\frac{11}{9}\)
3
\(\frac{9}{\sqrt{202}}\)
4
\(\frac{9}{11}\)

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