\(a-\frac{12}{a}=1\) ಆಗಿದ್ದರೆ, ಅಲ್ಲಿ a > 0, ಆಗ \(a^2+\frac{16}{a^2}\) ಮೌಲ್ಯವು:

1
15
2
19
3
17
4
11

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