ಒಂದು ವೇಳೆ x = \(\frac{(1.75)^2-(1.62)^2}{0.13}\) x = ಆಗಿದ್ದರೆ, x ನ ಮೌಲ್ಯವು ಏನಾಗಿರುತ್ತದೆ?

1
3.37
2
3.38
3
7.33 
4
7.03

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