\(\tan x=\frac{\sin \theta+\cos \theta}{\sin \theta-\cos \theta} \) ಎಂದು ಕೊಟ್ಟಿದ್ದರೆ, \(\frac{\pi}{4}<\theta<\frac{\pi}{2} \), ಆಗ √2 sin x ಯು ಏನು?
1
sin θ + cos θ
2
sin θ - cos θ
3
\(\frac{\sin \theta+\cos \theta}{2}\)
4
\(\frac{\sin \theta-\cos \theta}{2}\)