ಒಂದು ವೇಳೆ  ತ್ರಿಕೋನದಲ್ಲಿ ∠B = 90° ಮತ್ತು A = 60° ಆಗಿದ್ದರೆ, Sin2A - Cos2A + Tan2A = ?

1
\(\frac{7}{2}\)
2
\(\frac{2}{5}\)
3
\(\frac{2}{3}\)
4
\(\frac{6}{5}\)

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