यदि (x + \(\rm \frac{1}{x}\)) = 2z, तब 'z' के पदों में x3 + \(\rm \frac{1}{x^3}\) है:

1
2z(4z2 - 3)
2
z(z2​ - 3)
3
z2​ - 4
4
z3​ - 8z2

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