engineering recuitment GATE ECE 2023-24 Test Series Control Systems Frequency Response Analysis Bode Plot
LTI प्रणाली के लिए, इसके लाभ के लिए बोडे प्लॉट दिखाए गए चित्र में दिखाया गया है। प्रणाली का स्थानांतरण फलन _____ है।
1
\(H\left( s \right) = \frac{{10^5\left( {1 + \frac{s}{{1000}}} \right){{\left( {1 + \frac{s}{{{{10}^4}}}} \right)}}}}{{\left( {1 + \frac{s}{{10}}} \right){{\left( {1 + \frac{s}{{100}}} \right)}^2}{{\left( {1 + \frac{s}{{{{10}^5}}}} \right)}^2}\left( {1 + \frac{s}{{{{10}^6}}}} \right)}}\)
2
\(H\left( s \right) = \frac{{10^5\left( {1 + \frac{s}{{1000}}} \right){{\left( {1 + \frac{s}{{{{10}^4}}}} \right)}^2}}}{{\left( {1 + \frac{s}{{10}}} \right){{\left( {1 + \frac{s}{{100}}} \right)}^2}{{\left( {1 + \frac{s}{{{{10}^5}}}} \right)}^2}\left( {1 + \frac{s}{{{{10}^6}}}} \right)}}\)
3
\(H\left( s \right) = \frac{{\left( {1 + \frac{s}{{1000}}} \right){{\left( {1 + \frac{s}{{{{10}^4}}}} \right)}^2}}}{{\left( {1 + \frac{s}{{10}}} \right){{\left( {1 + \frac{s}{{100}}} \right)}^2}{{\left( {1 + \frac{s}{{{{10}^5}}}} \right)}^2}\left( {1 + \frac{s}{{{{10}^6}}}} \right)^2}}\)
4
\(H\left( s \right) = \frac{{\left( {1 + \frac{s}{{1000}}} \right)^2{{\left( {1 + \frac{s}{{{{10}^4}}}} \right)}^2}}}{{\left( {1 + \frac{s}{{10}}} \right){{\left( {1 + \frac{s}{{100}}} \right)}^2}{{\left( {1 + \frac{s}{{{{10}^5}}}} \right)}^2}\left( {1 + \frac{s}{{{{10}^6}}}} \right)^2}}\)