असमिका \(\frac{(2-x)}{5}-\frac{(2-3 x)}{4} \leq \frac{(2 x-1)}{3}\) (जहाँ x एक वास्तविक संख्या है) को हल करें।

1
[-7, 7]
2
(-∞, 2]
3
[7, 14]
4
[2, ∞)

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