यदि sin θ cos θ = \(\frac{\sqrt2}{3}\) है, तो (sin6 θ + cos6 θ) का मान ज्ञात कीजिए

1
\(\frac{1}{3}\)
2
\(\frac{4}{3}\)
3
\(\frac{2}{3}\)
4
\(\frac{5}{3}\)

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