यदि x = 2 - √6 है, तो \({x^2} + \frac{{12}}{{{x^2}}} = \;?\)

1
\(\frac{{8\left( {13 - 5\sqrt 2 } \right)}}{{\left( {5 - 2\sqrt 2 } \right)}}\)
2
\(\frac{{8\left( {13 - 5\sqrt 6 } \right)}}{{\left( {1 - 2\sqrt 6 } \right)}}\)
3
\(\frac{{8\left( {1 - 5\sqrt 6 } \right)}}{{\left( {5 - 2\sqrt 6 } \right)}}\)
4
\(\frac{{8\left( {13 - 5\sqrt 6 } \right)}}{{\left( {5 - 2\sqrt 6 } \right)}}\)
5
अनुत्तरित प्रश्न

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