\(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} = \sqrt {1 + \sin 2{\rm{x}}}\) का सामान्य समाधान ज्ञात कीजिए जहाँ x \(\in\) [0, π]।

1
y = cos 2x + c
2
y = x + 2 cos 2x + c
3
y = sin x - cos x + c
4
y = cos x + sin x + c

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