यदि \(z=\frac{1+i √{3}}{1-i √{3}}\) है, जहां i = √-1 है, तो z का कोणांक क्या है? 

1
\(\frac{\pi}{3}\)
2
\(\frac{2\pi}{3}\)
3
\(\frac{4\pi}{3}\)
4
\(\frac{5\pi}{6}\)

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