यदि cotθ = \(\sqrt{2+\sqrt{2 + \sqrt{2 + \sqrt{2 + ...}}} }\) जहाँ, 0 < θ < 90∘ है, तो tanθ का मान ज्ञात कीजिए।

1
\(\frac{1}{2}\)
2
√2
3
\(\frac{1}{\sqrt 2}\)
4
2

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