यदि \(f'(x) \ =\ sin^{-1}[2(\frac{2tanx\ -\ 2tan^3x}{sec^4x})]\) , \(\frac{-\pi}{2}\ <\ x\ <\ \frac{\pi}{2}\) और f(1) = 2 हो तो f(2) का मान क्या होगा?

1
-8
2
4
3
8
4
-4

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