એક ત્રિકોણમાં, ∠C = 90° અને ∠A = 60° હોય, તો sin A/2 + cosec A = ?

1
(√3 + 4)/2
2
(√3 + 4)/(2√3)
3
(√2 + 4)/(3√3)
4
(√3 + 4)/√3

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