નીચે આપેલ રેખીય સમીકરણ ઉકેલો.
2x - y + z = 8, x + y - z = 10, x + y + 2z = 12
1
x = \(\frac{2}{3}\), y = - 6, z = \(\frac{14}{3}\)
2
x = - 6, y = \(\frac{-14}{3}\), z = \(\frac{1}{3}\)
3
x = 6, y = \(\frac{14}{3}\), z = \(\frac{2}{3}\)
4
x = \(\frac{-1}{3}\), y = 6, z = \(\frac{14}{3}\)