Solve the given equations and answer the following question
I. x2 + 24x + 268 = (x + 12)2 + a + b
II.: 4y2 + 230 + 108y = (3y + 18)2 - 5y2 - b - с
III. z2 + (a - c)z + (10c - 100) = 0
Conditions:
i) c = \(\sqrt[3]{b}\) × 7.5
ii) a = \(\sqrt[3]{b}\) × 15
Find the highest root of equation III
1
-15
2
-5
3
-10
4
-20
5
None of these