Solve both equations and form a new equation in variable 'z' using the instructions given below.
(i) 3 - (28/x) + (3/x)2 = 0
(ii) (y - 3)2 = \(6{1 \over 4}\)
What will be the new equation if one root is the highest root of equation (i) and another root is the lowest root of equation (ii)?
1
2z2 - 19z + 9 = 0
2
2z2 - 19z - 9 = 0
3
2z2 + 19z + 9 = 0
4
2z2 + 19z - 9 = 0
5
2z2 - 9z + 19 = 0