Comprehension Passage

Direction: Study the following information and answer the questions mentioned below.

Mr. Mehta has four kids Ravi the oldest, Ria the second oldest, Raja the second youngest and, Ritu the youngest, and all were born on the same date of different years. They all have a birthday today. Mr. Mehta wants to buy chocolates for all his kids. But he doesn’t want to give each kid an equal number of chocolates.

He decides to do the following thing:

He will divide the height (in cm) by the sum of age numbers with weight (in kg).

He arrives at this formula – Number of chocolates = Height in centimeters / (weight in kilogram + age)

The number that will come is the number of chocolates that a particular kid will get.

His second youngest kid is two times the age of the Ritu whose age is one-third the oldest kid. Ria is three years younger than the oldest kid. The weight of the oldest kid is 36 kg that is numerically three times the age of the second oldest kid, whose weight is four times the age of Raja. The weight of Ritu is 40% less than the second oldest kid. The sum of the weight of all four kids is 129 kg.

After 5 years from this birthday, Mr. Mehta repeat the same method of distributing the chocolates. After 5 years, his youngest kid has gained 25% while the oldest kid has weight twice the youngest kid. He distributes 6 chocolates between the youngest and the oldest kid. If their heights are equal then choose the correct option.

1
Youngest kid gets 2 chocolate
2
Oldest kid gets 4 chocolate
3
Height is 156 cm each
4
Height is 160 cm each
5
None of the above

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation