If \(\frac{1}{6}\) sin θ cos θ, tan θ are in G.P, then the solution set of θ is (Here n ∈ ℕ)

1
\(\rm 2n\pi \pm\frac{\pi}{6}\)
2
\(\rm 2n\pi \pm\frac{\pi}{3}\)
3
\(\rm n\pi +(-1)^n\frac{\pi}{3}\)
4
\(\rm n\pi +\frac{\pi}{3}\)

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